The binding energy of a nucleus is a measure of its

Two nuclei of mass number $3$ combine with another nucleus of mass number $4$ to yield a nucleus of mass number $10$. If the binding energy per nucleon for the mass numbers $3$, $4$, and $10$ are $5.6 \text{ MeV}$, $7.4 \text{ MeV}$, and $6.1 \text{ MeV}$, respectively, then in the process, $\Delta Mc^2 = . . . . . . \text{ MeV}$.

The mass equivalent of $931\, MeV$ energy is

The mass defect per nucleon is called

$A$ nucleus of mass $M + \Delta m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. The speed of light is $c$. The binding energy per nucleon for the parent nucleus is $E_1$ and that for the daughter nuclei is $E_2$. Then:

In the nuclear reaction $_1^2H + _1^3H \to _2^4He + _0^1n$, if the binding energies of $_1^2H$, $_1^3H$, and $_2^4He$ are respectively $a$, $b$, and $c$ (in $MeV$), then the energy (in $MeV$) released in this reaction is: