The binding energy of the innermost electron in tungsten is $40 \text{ keV}$. To produce characteristic $X$-rays using a tungsten target in an $X$-ray tube,the potential difference $V$ between the cathode and the anti-cathode should be:

  • A
    $V < 40 \text{ kV}$
  • B
    $V \le 40 \text{ kV}$
  • C
    $V > 40 \text{ kV}$
  • D
    $V >/< 40 \text{ kV}$

Explore More

Similar Questions

The structure of solid crystals is investigated by using

When $0.50\; \mathring{A}$ $X$-rays strike a material,the photoelectrons from the $K$-shell are observed to move in a circle of radius $23\; mm$ in a magnetic field of $2 \times 10^{-2}\; T$ acting perpendicularly to the direction of emission of photoelectrons. The binding energy of $K$-shell electrons is $..........\; keV$.

Difficult
View Solution

When $X-$rays pass through a strong uniform magnetic field,then they

$20 \ kV$ electrons can produce $X$-rays with a minimum wavelength of

The potential difference applied to an $X-$ray tube is increased. As a result,in the emitted radiation:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo