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(B) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L_{eff}}{g}}$,where $L_{eff}$ is the distance between the point of suspensi

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first increase and then decrease to the original value

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(B) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L_{eff}}{g}}$,where $L_{eff}$ is the distance between the point of suspension and the center of mass of the bob.Initially,the center of mass of the water-filled sphere is at its geometric center.As water starts leaking out from the bottom,the center of mass of the remaining water shifts downwards. This increases the effective length $L_{eff}$ of the pendulum.Since $T \propto \sqrt{L_{eff}}$,the time period $T$ increases as the center of mass moves down.When the water is completely drained,the center of mass returns to the geometric center of the sphere,so the effective length returns to its original value,and the time period decreases back to its original value.Therefore,the time period first increases and then decreases to the original value.

The bob of a simple pendulum is a spherical hollow ball filled with water. $A$ plugged hole near the bottom of the oscillating bob gets suddenly unplugged. During observation,till water is coming out,the time period of oscillation would

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