The bond angle in a water molecule is nearly | vedclass

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Question

(D) In a water molecule $(H_2O)$,the central oxygen atom undergoes $sp^3$ hybridization.According to the $VSEPR$ theory,the presence of two lone pairs

Vedclass · Accepted Answer

$104^o 30'$

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(D) In a water molecule $(H_2O)$,the central oxygen atom undergoes $sp^3$ hybridization.According to the $VSEPR$ theory,the presence of two lone pairs on the oxygen atom causes repulsion,which compresses the bond angle from the ideal tetrahedral angle of $109^o 28'$ to approximately $104.5^o$ (often represented as $104^o 30'$).Therefore,the correct option is $(d)$.

The bond angle in a water molecule is nearly or directed bonds in water form an angle of:

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