The bond in the formation of fluorine molecul | vedclass

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(C) The atomic number of fluorine $(F)$ is $9$. Its electronic configuration is $1s^2 2s^2 2p_x^2 2p_y^2 2p_z^1$. In the formation of a fluorine molec

Vedclass · Accepted Answer

Due to $p - p$ overlapping

Vedclass · Answer

(C) The atomic number of fluorine $(F)$ is $9$. Its electronic configuration is $1s^2 2s^2 2p_x^2 2p_y^2 2p_z^1$. In the formation of a fluorine molecule $(F_2)$,the half-filled $2p_z$ orbital of one fluorine atom overlaps with the half-filled $2p_z$ orbital of another fluorine atom. This is an example of $p - p$ overlapping along the internuclear axis,resulting in the formation of a sigma bond.

The bond in the formation of fluorine molecule will be

Similar Questions

According to the $VB$ theory,when is a bond not formed between two atoms? Give examples.

The number of sigma $(\sigma)$ and pi $(\pi)$ bonds present in benzene respectively are:

The double bond between the two carbon atoms in ethylene $(CH_2=CH_2)$ consists of:

The number of $\sigma$ and $\pi$ bonds in sulfuric acid $(H_2SO_4)$ are respectively:

Which of the following combinations does not form a $\sigma$ bond?
$(i) \ 2p_y - 2p_y$
$(ii) \ 2p_z - 2p_z$
$(iii) \ 2s - 2p_x$
$(iv) \ 2p_x - 2p_x$

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