The bond length of HCl molecule is 1.275 mat | vedclass

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(D) Given:Observed dipole moment $= 1.03 \ D$Bond length of $HCl$ molecule,$d = 1.275 \ \mathring{A} = 1.275 	imes 10^{-8} \ cm$Charge of electron,$e

Vedclass · Accepted Answer

$16.83$

Vedclass · Answer

(D) Given:Observed dipole moment $= 1.03 \ D$Bond length of $HCl$ molecule,$d = 1.275 \ \mathring{A} = 1.275 	imes 10^{-8} \ cm$Charge of electron,$e = 4.8 	imes 10^{-10} \ esu$Theoretical dipole moment $= e 	imes d = (4.8 	imes 10^{-10} \ esu) 	imes (1.275 	imes 10^{-8} \ cm) = 6.12 	imes 10^{-18} \ esu \cdot cm = 6.12 \ D$Percentage ionic character $= \frac{	ext{Observed dipole moment}}{	ext{Theoretical dipole moment}} 	imes 100$Percentage ionic character $= \frac{1.03}{6.12} 	imes 100 = 16.83 \%$

The bond length of $HCl$ molecule is $1.275 \ \mathring{A}$ and its dipole moment is $1.03 \ D$. The ionic character of the molecule (in percent) (charge of the electron $= 4.8 \times 10^{-10} \ esu$) is

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