The bond order of O_2^+ is the same as in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total number of electrons in $O_2^+$ is $15$. The molecular orbital configuration is $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^

Vedclass · Accepted Answer

$N_2^+$

Vedclass · Answer

(A) The total number of electrons in $O_2^+$ is $15$. The molecular orbital configuration is $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^2(\pi^* 2p_x)^1$. Bond order $= \frac{1}{2}(N_b - N_a) = \frac{1}{2}(10 - 5) = 2.5$. The total number of electrons in $N_2^+$ is $13$. The molecular orbital configuration is $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^1$. Bond order $= \frac{1}{2}(9 - 4) = 2.5$. Thus,the bond order of $O_2^+$ is the same as that of $N_2^+$.

The bond order of $O_2^+$ is the same as in

Similar Questions

The molecule having one unpaired electron is

The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements?

What is the bond order in $N_{2}$ molecule?

How many among the given species have a bond order of $0.5$?
$H_2^{+}, He_2^{+}, He_2^{-}, B_2^{+}, F_2^{-}, Be_2^{2-}$

Which of the following pairs of species have the same bond order?

Vedclass Test Series

Exam Paper Generator

Online Exam Module