(A) The total number of electrons in $HeH^{+}$ is $2 + 1 - 1 = 2$. The molecular orbital electronic configuration is $\sigma_{1s}^2$. Bond Order $= \f

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(A) The total number of electrons in $HeH^{+}$ is $2 + 1 - 1 = 2$. The molecular orbital electronic configuration is $\sigma_{1s}^2$. Bond Order $= \frac{1}{2} [N_b - N_a] = \frac{1}{2} [2 - 0] = 1$.

Class 11 Chemistry Chemical Bonding and Molecular Structure Molecular orbital theory

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The bond order of $HeH^{+}$ is

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A
$1$
B
$2$
C
$3$
D
$4$

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The bond order of $HeH^{+}$ is

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