(C) The molecular orbital configuration of $CO$ ($14$ electrons) is: $\sigma(1s)^2, \sigma^*(1s)^2, \sigma(2s)^2, \sigma^*(2s)^2, \pi(2p_x)^2 = \pi(2p

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(C) The molecular orbital configuration of $CO$ ($14$ electrons) is: $\sigma(1s)^2, \sigma^*(1s)^2, \sigma(2s)^2, \sigma^*(2s)^2, \pi(2p_x)^2 = \pi(2p_y)^2, \sigma(2p_z)^2$. Number of bonding electrons $(N_b)$ = $10$. Number of antibonding electrons $(N_a)$ = $4$. Bond Order = $\frac{N_b - N_a}{2} = \frac{10 - 4}{2} = 3$.