The bond order values of anions of sodium per | vedclass

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Question

(A) Sodium peroxide $(Na_2O_2)$ contains the peroxide anion $O_2^{2-}$.Potassium superoxide $(KO_2)$ contains the superoxide anion $O_2^-$.For $O_2^{2

Vedclass · Accepted Answer

$1, 1.5$

Vedclass · Answer

(A) Sodium peroxide $(Na_2O_2)$ contains the peroxide anion $O_2^{2-}$.Potassium superoxide $(KO_2)$ contains the superoxide anion $O_2^-$.For $O_2^{2-}$: Total electrons = $18$. Electronic configuration: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$.Bond order = $\frac{10 - 8}{2} = 1$.For $O_2^-$: Total electrons = $17$. Electronic configuration: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^1$.Bond order = $\frac{10 - 7}{2} = 1.5$.

The bond order values of anions of sodium peroxide and potassium superoxide are respectively:

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