The bonds in {K_4[Fe(CN)_6]} are | vedclass

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Question

(D) The compound ${K_4[Fe(CN)_6]}$ consists of $4K^+$ ions and the complex ion $[Fe(CN)_6]^{4-}$.$1$. The bond between $K^+$ and $[Fe(CN)_6]^{4-}$ is

Vedclass · Accepted Answer

Ionic,covalent and coordinate covalent

Vedclass · Answer

(D) The compound ${K_4[Fe(CN)_6]}$ consists of $4K^+$ ions and the complex ion $[Fe(CN)_6]^{4-}$.$1$. The bond between $K^+$ and $[Fe(CN)_6]^{4-}$ is ionic.$2$. Within the cyanide ligand $(CN^-)$,there is a triple bond between $C$ and $N$,which is covalent.$3$. The bond between the $Fe^{2+}$ central metal ion and the $C$ atom of the $CN^-$ ligand is a coordinate covalent bond (dative bond),where the $CN^-$ ligand donates a lone pair of electrons to the $Fe^{2+}$ ion.Therefore,the compound contains ionic,covalent,and coordinate covalent bonds.

The bonds in ${K_4[Fe(CN)_6]}$ are

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