The Boolean equation for the circuit given in | vedclass

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(C) In the given circuit,we have a combination of a $NOT$ gate and an $OR$ gate.For the $NOT$ gate,the input is $A$,so the output is $X = \bar{A}$.Thi

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$Y=\bar{A}+B$

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(C) In the given circuit,we have a combination of a $NOT$ gate and an $OR$ gate.For the $NOT$ gate,the input is $A$,so the output is $X = \bar{A}$.This output $X$ acts as one of the inputs to the $OR$ gate,while $B$ is the other input.For the $OR$ gate,the output $Y$ is the sum of its inputs:$Y = X + B$Substituting the value of $X$ from the $NOT$ gate:$Y = \bar{A} + B$Thus,the Boolean expression for the given circuit is $Y = \bar{A} + B$.

The Boolean equation for the circuit given in the figure is

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