The Boolean expression $(p \wedge \sim q) \Rightarrow (q \vee \sim p)$ is equivalent to:

  • A
    $p \Rightarrow q$
  • B
    $q \Rightarrow p$
  • C
    $p \Rightarrow \sim q$
  • D
    $\sim q \Rightarrow p$

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Consider
Statement-$1$: $(p \wedge \sim q) \wedge (\sim p \wedge q)$ is a fallacy.
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