The Boolean expression of the circuit given in the figure is

  • A
    $Y=A+\bar{B}$
  • B
    $Y=\overline{A+B}$
  • C
    $Y=\bar{A}+B$
  • D
    $Y=A+B$

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Similar Questions

In the Boolean algebra,the expression $\left( {\overline {\bar A \cdot \bar B} } \right) \cdot A$ is equal to:

In the circuit,the logical value of $A = 1$ or $B = 1$ when the potential at $A$ or $B$ is $5 \, V$,and the logical value of $A = 0$ or $B = 0$ when the potential at $A$ or $B$ is $0 \, V$. The truth table of the given circuit will be:

The truth table for the circuit given below is $:$

To get an output $Y = 1$ from the logic circuit shown in the figure,the inputs can be:

Identify the equivalent logic gate represented by the given circuit.

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