The buffer system which helps to maintain the $pH$ of blood between $7.26$ to $7.42$ is:

  • A
    $H_2CO_3 / HCO_3^{-}$
  • B
    $NH_4OH / NH_4Cl$
  • C
    $CH_3COOH / CH_3COO^{-}$
  • D
    $CH_3COONH_4$

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If $12.5 \ mL$ of $0.1 \ M$ $KOH$ is added into $50 \ mL$ of $0.1 \ M$ $CH_3COOH$ solution,then what would be the final $pH$? $(K_a(CH_3COOH) = 2 \times 10^{-5})$

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