The calculated spin-only magnetic moment of C | vedclass

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(B) The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.The electronic configuration of $Cr^{2+}$ ion is $[Ar] 3d^4 4s^0$.Number of unpaired elec

Vedclass · Accepted Answer

$4.90$

Vedclass · Answer

(B) The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.The electronic configuration of $Cr^{2+}$ ion is $[Ar] 3d^4 4s^0$.Number of unpaired electrons $(n)$ = $4$.The spin-only magnetic moment formula is $\mu = \sqrt{n(n+2)} 	ext{ BM}$.Substituting $n = 4$ into the formula: $\mu = \sqrt{4(4+2)} = \sqrt{4 	imes 6} = \sqrt{24} \approx 4.90 	ext{ BM}$.

The calculated spin-only magnetic moment of $Cr^{2+}$ ion is: (in $text{ BM}$)

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