The Cannizzaro reaction is not given by . . . . . . .

  • A
    $HCHO$
  • B
    $C_6H_5CHO$
  • C
    $1\text{-methylcyclohexanecarbaldehyde}$
  • D
    $CH_3CHO$

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Which of the following is $D$ in the given reaction sequence?
$(CH_3)_3C-CH_2OH$ $\xrightarrow{PCC} B$ $\xrightarrow{Conc. NaOH} A + C$ $\xrightarrow{NaOH/CaO, \Delta} D$

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Match the example given in Column-$I$ with the name of the reaction in Column-$II$.
Column-$I$ (Example)Column-$II$ (Reaction)
$(A)$ $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$$(1)$ Friedel-Crafts acylation
$(B)$ $C_6H_5CHO \xrightarrow{NaOH} C_6H_5CH_2OH + C_6H_5COONa$$(2)$ $HVZ$ reaction
$(C)$ $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$$(3)$ Aldol condensation
$(D)$ $R-CH_2COOH \xrightarrow{Br_2/Red P} R-CH(Br)COOH$$(4)$ Cannizzaro's reaction
$(E)$ $CH_3-CN \xrightarrow{SnCl_2/HCl, H_2O/H^+} CH_3-CHO$$(5)$ Rosenmund's reduction
$(F)$ $2CH_3CHO \xrightarrow{NaOH} CH_3-CH=CH-CHO$$(6)$ Stephen's reaction

Which of the following will not give the iodoform test?

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