The capacity of a tank,in the form of a cylin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The radius of the base of the cylinder is $r = \frac{28}{2} = 14 \, m$.Let $h$ be the depth (height) of the tank.The capacity (volume) of the tank

Vedclass · Accepted Answer

$2464$

Vedclass · Answer

(A) The radius of the base of the cylinder is $r = \frac{28}{2} = 14 \, m$.Let $h$ be the depth (height) of the tank.The capacity (volume) of the tank is given by $V = \pi r^2 h = 6160 \, m^3$.Substituting the values: $\frac{22}{7} 	imes 14 	imes 14 	imes h = 6160$.$22 	imes 2 	imes 14 	imes h = 6160 \implies 616 	imes h = 6160 \implies h = 10 \, m$.The inner curved surface area is $A = 2 \pi r h = 2 	imes \frac{22}{7} 	imes 14 	imes 10 = 880 \, m^2$.The cost of painting the inner curved surface at the rate of ₹ $2.8$ per $m^2$ is $880 	imes 2.8 = ₹ 2464$.

The capacity of a tank,in the form of a cylinder,is $6160 \, m^3$. If the diameter of its base is $28 \, m$,find out the cost of painting its inner curved surface at the rate of ₹ $2.8$ per $m^2$. (Use $\pi = \frac{22}{7}$)

Similar Questions

If three metallic spheres of radii $6\, cm$,$8\, cm$,and $10\, cm$ are melted to form a single sphere,the diameter of the new sphere will be (in $cm$)?

The edges of a cuboid are in the ratio $1: 2: 3,$ and its surface area is $88 \, cm^2.$ The volume of the cuboid is ........ $cm^3$.

The material of a solid cone is converted into the shape of a solid cylinder of equal radius. If the height of the cylinder is $5\,cm$,then what is the height of the cone? (in $cm$)

$A$ brick measures $20 \, cm$ by $10 \, cm$ by $7.5 \, cm$. How many bricks will be required to construct a wall $25 \, m$ long,$2 \, m$ high,and $0.75 \, m$ thick?

$A$ right circular cylindrical tunnel of diameter $5\, m$ and length $10\, m$ is to be constructed from a sheet of iron. The area of iron sheet required will be..........$\pi\, m^2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module