The cathode of a photoelectric cell is change | vedclass

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(A) The photoelectric current depends on the number of photoelectrons emitted per unit time.This number is directly proportional to the intensity of t

Vedclass · Accepted Answer

$I_1 = I_2$

Vedclass · Answer

(A) The photoelectric current depends on the number of photoelectrons emitted per unit time.This number is directly proportional to the intensity of the incident light,provided the energy of the incident photons $(hv)$ is greater than the work function $(W)$ of the metal surface.Since the condition $hv > W_2$ is satisfied (which implies $hv > W_1$ as well),every incident photon that was capable of ejecting an electron before the change is still capable of doing so after the change.Because the intensity of the incident light remains unchanged,the rate of emission of photoelectrons remains the same.Therefore,the photoelectric current remains constant,i.e.,$I_1 = I_2$.

The cathode of a photoelectric cell is changed such that the work function changes from $W_1$ to $W_2$ $(W_2 > W_1)$. If the current before and after the change are $I_1$ and $I_2$,respectively,and all other conditions remain unchanged,then (assuming $hv > W_2$):

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