The cell constant of a given cell is $0.47 \, cm^{-1}$. The resistance of a solution placed in this cell is measured to be $31.6 \, \Omega$. The conductivity of the solution (in $S \, cm^{-1}$ where $S$ has usual meaning) is

Which is the conductivity of $0.02 \ M \ HCl$ solution if molar conductivity of the solution at $25^{\circ} C$ is $412.3 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$?

The electrodes of a conductivity cell are $3 \text{ cm}$ apart and have a cross-sectional area of $4 \text{ cm}^2$. The cell constant of the cell (in $\text{cm}^{-1}$) is

The molar conductivities $\Lambda_{NaOH}^o$ and $\Lambda_{HCl}^o$ at infinite dilution in water at $25 ^\circ C$ are $91.0$ and $426.2 \ S \ cm^2/mol$ respectively. To calculate $\Lambda_{CH_3COOH}^o$,the additional value required is:

The specific conductivities (in $\Omega^{-1} \text{ cm}^{-1}$) of four electrolytes $P, Q, R,$ and $S$ are given in the brackets. Which one offers the maximum resistance when current is passed through them?
$P (5.0 \times 10^{-5}), Q (7.0 \times 10^{-8}), R (1.0 \times 10^{-10}), S (9.2 \times 10^{-3})$

The resistance of a conductivity cell with cell constant $1.14 \, cm^{-1}$,containing $0.001 \, M \, KCl$ at $298 \, K$ is $1500 \, \Omega$. The molar conductivity of $0.001 \, M \, KCl$ solution at $298 \, K$ in $S \, cm^{2} \, mol^{-1}$ is ...... . (Integer answer)