(B) In a cell representation,the anode (oxidation) is written on the left and the cathode (reduction) is written on the right.Here,$Mn$ is oxidized to

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$Mn|Mn^{+2}(C_2) || Ag^{+}(C_1)|Ag$

(B) In a cell representation,the anode (oxidation) is written on the left and the cathode (reduction) is written on the right.Here,$Mn$ is oxidized to $Mn^{+2}$ at the anode: $Mn \to Mn^{+2} + 2e^-$.$Ag^+$ is reduced to $Ag$ at the cathode: $2Ag^+ + 2e^- \to 2Ag$.The salt bridge is represented by $||$.Thus,the cell representation is $Mn|Mn^{+2}(C_2) || Ag^{+}(C_1)|Ag$.

Class 12 Chemistry Electrochemistry Electrochemical cells

Medium

The cell reaction $Mn + 2Ag_{(C_1)}^{+(aq)} \to Mn_{(C_2)}^{+2_{(aq)}} + 2Ag$ is represented by

A
$Ag|Ag^{+}(C_1) || Mn|Mn^{+2}(C_2)$
B
$Mn|Mn^{+2}(C_2) || Ag^{+}(C_1)|Ag$
C
$2Ag|Ag^{+}(C_1) || Mn|Mn^{+2}(C_2)$
D
$Mn|Mn^{+2}(C_2) || 2Ag|Ag^{+}(C_1)$

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Electrochemistry

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Electrochemical cells

The correct formula of calomel is:

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Which of the following statements is true for a standard electrochemical cell consisting of $H_2$ and $Cu$ electrodes?

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What is the reaction occurring at the anode in a $CH_4 - O_2$ fuel cell?

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Assertion : For the Daniel cell,$Zn|Zn^{2+} || Cu^{2+}|Cu$ with $E_{cell} = 1.1 \ V$,the application of an opposite potential greater than $1.1 \ V$ results in the flow of electrons from cathode to anode.
Reason : $Zn$ is deposited at the anode,and $Cu$ is deposited at the cathode.

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The reference electrode,specifically the Saturated Calomel Electrode $(SCE)$,is made from which of the following substances?

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The cell reaction $Mn + 2Ag_{(C_1)}^{+(aq)} \to Mn_{(C_2)}^{+2_{(aq)}} + 2Ag$ is represented by

Similar Questions

The correct formula of calomel is:

Which of the following statements is true for a standard electrochemical cell consisting of $H_2$ and $Cu$ electrodes?

What is the reaction occurring at the anode in a $CH_4 - O_2$ fuel cell?

Assertion : For the Daniel cell,$Zn|Zn^{2+} || Cu^{2+}|Cu$ with $E_{cell} = 1.1 \ V$,the application of an opposite potential greater than $1.1 \ V$ results in the flow of electrons from cathode to anode.Reason : $Zn$ is deposited at the anode,and $Cu$ is deposited at the cathode.

The reference electrode,specifically the Saturated Calomel Electrode $(SCE)$,is made from which of the following substances?

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Assertion : For the Daniel cell,$Zn|Zn^{2+} || Cu^{2+}|Cu$ with $E_{cell} = 1.1 \ V$,the application of an opposite potential greater than $1.1 \ V$ results in the flow of electrons from cathode to anode.
Reason : $Zn$ is deposited at the anode,and $Cu$ is deposited at the cathode.