The chemical reaction,$2AgCl_{(s)} + H_{2(g)} \to 2HCl_{(aq)} + 2Ag_{(s)}$ taking place in a galvanic cell is represented by the notation:

  • A
    $Pt | H_{2(g)}, 1 \ bar | 1 \ M \ KCl_{(aq)} | AgCl_{(s)} | Ag_{(s)}$
  • B
    $Pt_{(s)} | H_{2(g)}, 1 \ bar | 1 \ M \ HCl_{(aq)} || 1 \ M \ Ag^{+}_{(aq)} | Ag_{(s)}$
  • C
    $Pt_{(s)} | H_{2(g)}, 1 \ bar | 1 \ M \ HCl_{(aq)} | AgCl_{(s)} | Ag_{(s)}$
  • D
    $Pt_{(s)} | H_{2(g)}, 1 \ bar | 1 \ M \ HCl_{(aq)} | Ag_{(s)} | AgCl_{(s)}$

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$(ii)$ If cell $'A'$ has $E_{cell} = 0.5 \ V$ and cell $'B'$ has $E_{cell} = 1.1 \ V$,then what will be the reaction at the anode and cathode?

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