The circular coil of a galvanometer has 50 tu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The deflection $\phi$ of a moving coil galvanometer is given by the formula: $\phi = \frac{N A B i}{k}$.Here, $N = 50$, $r = 1 \ cm = 0.01 \ m$, $

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(B) The deflection $\phi$ of a moving coil galvanometer is given by the formula: $\phi = \frac{N A B i}{k}$.Here, $N = 50$, $r = 1 \ cm = 0.01 \ m$, $B = 0.010 \ T$, $i = 1.0 \ mA = 1.0 	imes 10^{-3} \ A$, and $k = 3 	imes 10^{-7} \ N-m-rad^{-1}$.The area $A = \pi r^2 = \pi 	imes (0.01)^2 = \pi 	imes 10^{-4} \ m^2$.Substituting these values into the formula:$\phi = \frac{50 	imes (\pi 	imes 10^{-4}) 	imes 0.010 	imes 1.0 	imes 10^{-3}}{3 	imes 10^{-7}}$$\phi = \frac{50 	imes \pi 	imes 10^{-4} 	imes 10^{-2} 	imes 10^{-3}}{3 	imes 10^{-7}} = \frac{50 	imes \pi 	imes 10^{-9}}{3 	imes 10^{-7}} = \frac{50 	imes \pi}{3} 	imes 10^{-2} = \frac{0.5 \pi}{3} \approx 0.5236 \ radians$.Converting radians to degrees: $\phi_{deg} = 0.5236 	imes \frac{180}{\pi} = 30^{\circ}$.

Similar Questions

$A$ galvanometer coil has a resistance of $10 \ \Omega$ and the meter shows full-scale deflection for $3 \ \text{mA}$. The value of the shunt required to convert this meter into an ammeter of range $0$ to $10 \ \text{A}$ is . . . . . . $\Omega$.

When a $12\,\Omega$ resistor is connected in parallel with a moving coil galvanometer,its deflection reduces from $50$ divisions to $10$ divisions. The resistance of the galvanometer is ............. $\Omega$.

The sensitivity of a moving coil galvanometer is $s$. If a shunt of $\frac{1}{8}$ of the resistance of the galvanometer is connected to the moving coil galvanometer,what will its new sensitivity be?

When a resistance of $200 \Omega$ is connected in series with a galvanometer of resistance $G$,its range is $V$. To triple its range,a resistance of $2000 \Omega$ is connected in series. The value of $G$ is (in $\Omega$)

$A$ galvanometer has $36\,\Omega$ resistance. If a $4\,\Omega$ shunt is added to this,the fraction of current that passes through the shunt is

Vedclass Test Series

Exam Paper Generator

Online Exam Module