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(D) For the smaller circle,the circumference $C_1 = 2 \pi r = 88 	ext{ m}$.Using $\pi = \frac{22}{7}$,we have $2 	imes \frac{22}{7} 	imes r = 88$,w

Vedclass · Accepted Answer

$3234$

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(D) For the smaller circle,the circumference $C_1 = 2 \pi r = 88 	ext{ m}$.Using $\pi = \frac{22}{7}$,we have $2 	imes \frac{22}{7} 	imes r = 88$,which gives $r = \frac{88 	imes 7}{44} = 14 	ext{ m}$.For the larger circle,the circumference $C_2 = 2 \pi R = 220 	ext{ m}$.$2 	imes \frac{22}{7} 	imes R = 220$,which gives $R = \frac{220 	imes 7}{44} = 35 	ext{ m}$.The difference between the areas is $\pi R^2 - \pi r^2 = \pi(R^2 - r^2)$.Difference $= \frac{22}{7} 	imes (35^2 - 14^2) = \frac{22}{7} 	imes (35 - 14)(35 + 14)$.Difference $= \frac{22}{7} 	imes 21 	imes 49 = 22 	imes 3 	imes 49 = 3234 	ext{ m}^2$.

The circumference of two circles is $88 \text{ m}$ and $220 \text{ m}$ respectively. What is the difference between the area of the larger circle and that of the smaller circle (in $m^2$)?

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