The coordination number of Ba^{2+} ion in Bar | vedclass

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(C) The coordination number of $Ba^{2+}$ is $8$. In an ionic crystal,the ratio of the coordination numbers of the ions is inversely proportional to th

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$4$

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(C) The coordination number of $Ba^{2+}$ is $8$. In an ionic crystal,the ratio of the coordination numbers of the ions is inversely proportional to the ratio of their stoichiometry. For $BaF_2$,the stoichiometry ratio is $Ba:F = 1:2$. Therefore,$\frac{C.N.(Ba^{2+})}{C.N.(F^{-})} = \frac{2}{1}$. Substituting the given value: $\frac{8}{C.N.(F^{-})} = \frac{2}{1}$. Solving for $C.N.(F^{-})$ gives $C.N.(F^{-}) = 4$.

The coordination number of $Ba^{2+}$ ion in Barium fluoride $(BaF_2)$ is $8$. What must be the coordination number of fluoride ion $(F^{-})$?

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