The coefficient of mutual induction is $2 \text{ H}$ and the induced e.m.f. across the secondary is $2 \text{ kV}$. The current in the primary is reduced from $6 \text{ A}$ to $3 \text{ A}$. The time required for the change of current is:
- A$4 \times 10^{-3} \text{ s}$
- B$6 \times 10^{-3} \text{ s}$
- C$2 \times 10^{-3} \text{ s}$
- D$3 \times 10^{-3} \text{ s}$
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