(B) The necessary centripetal force for a car on a curved unbanked road is provided by the static friction force between the tyres and the road.For sa

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The necessary centripetal force for a car on a curved unbanked road is provided by the static friction force between the tyres and the road.For safe turning,the centripetal force must be less than or equal to the maximum static friction force:$\frac{mV^2}{r} \leq \mu mg$To find the maximum radius $r$ for a given speed $V$,we use the limiting case:$\frac{mV^2}{r} = \mu mg$$r = \frac{V^2}{\mu g}$Given values are $V = 10 \,ms^{-1}$,$\mu = 0.4$,and $g = 10 \,ms^{-2}$.Substituting these values into the equation:$r = \frac{10^2}{0.4 \times 10}$$r = \frac{100}{4}$$r = 25 \,m$Thus,the maximum radius of curvature is $25 \,m$.

Class 11 Physics Laws of Motion Circular motion with Friction

Easy

The coefficient of static friction between the road and tyres of a car is $0.4$. The maximum permissible speed of the car is $10 \,ms^{-1}$ on a curved unbanked road. Then the maximum radius of curvature of the road is (acceleration due to gravity $= 10 \,ms^{-2}$)

AP EAMCET 2022 All AP EAMCET

A
$10 \sqrt{5} \,m$
B
$25 \,m$
C
$20 \sqrt{2} \,m$
D
$30 \,m$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Laws of Motion

Subtopic

Circular motion with Friction

Previous Year

AP EAMCET 2022 Paper All AP EAMCET years →

$A$ child starts running from rest along a circular track of radius $r$ with constant tangential acceleration $a$. After time $t$,the child feels that the shoes have started slipping on the ground. What is the coefficient of friction $\mu$ between the shoes and the ground? $[g = \text{acceleration due to gravity}]$

DifficultMHT CET 2020

View Solution

$A$ disc rotates about its axis of symmetry in a horizontal plane at a steady rate of $3.5$ revolutions per second. $A$ coin placed at a distance of $1.25\,cm$ from the axis of rotation remains at rest on the disc. Find the coefficient of friction between the coin and the disc. (Take $g = 10\,m/s^2$)

DifficultJEE MAIN 2018

View Solution

$A$ car turns a corner on a slippery road at a constant speed of $10\,m/s$. If the coefficient of friction is $0.5$,the minimum radius of the arc in meters in which the car turns is:

Medium

View Solution

$A$ block of mass $m$ is kept on a horizontal turntable at a distance $x$ from the center. If the coefficient of friction between the block and the surface of the turntable is $\mu$,what is the maximum angular speed of the table so that the block does not slip?

Medium

View Solution

$A$ car is moving on a horizontal circular road of radius $0.1 \, km$ with constant speed. If the coefficient of friction between the tyres of the car and the road is $0.4$,then the speed of the car may be ......... $m/s$ $(g = 10 \, m/s^2)$.

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The coefficient of static friction between the road and tyres of a car is $0.4$. The maximum permissible speed of the car is $10 \,ms^{-1}$ on a curved unbanked road. Then the maximum radius of curvature of the road is (acceleration due to gravity $= 10 \,ms^{-2}$)

Similar Questions

$A$ car turns a corner on a slippery road at a constant speed of $10\,m/s$. If the coefficient of friction is $0.5$,the minimum radius of the arc in meters in which the car turns is:

$A$ block of mass $m$ is kept on a horizontal turntable at a distance $x$ from the center. If the coefficient of friction between the block and the surface of the turntable is $\mu$,what is the maximum angular speed of the table so that the block does not slip?

$A$ car is moving on a horizontal circular road of radius $0.1 \, km$ with constant speed. If the coefficient of friction between the tyres of the car and the road is $0.4$,then the speed of the car may be ......... $m/s$ $(g = 10 \, m/s^2)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module