The coefficients x, y, p, q, and r in the fol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given reaction is a disproportionation reaction where $Mn$ in $MnO_4^{2-}$ is oxidized and reduced.
Step $1$: Write the half-reactions.
Oxid

Vedclass · Accepted Answer

$3, 2, 1, 2, 4$

Vedclass · Answer

(D) The given reaction is a disproportionation reaction where $Mn$ in $MnO_4^{2-}$ is oxidized and reduced.
Step $1$: Write the half-reactions.
Oxidation: $MnO_4^{2-} \rightarrow MnO_4^{-} + e^-$
Reduction: $MnO_4^{2-} + 2H_2O + 2e^- \rightarrow MnO_2 + 4OH^{-}$
Step $2$: Balance the electrons by multiplying the oxidation half-reaction by $2$.
$2MnO_4^{2-} \rightarrow 2MnO_4^{-} + 2e^-$
$MnO_4^{2-} + 2H_2O + 2e^- \rightarrow MnO_2 + 4OH^{-}$
Step $3$: Add the two half-reactions:
$3MnO_4^{2-} + 2H_2O \rightarrow MnO_2 + 2MnO_4^{-} + 4OH^{-}$
Comparing this with the given equation, we get $x=3, y=2, p=1, q=2, r=4$.
Thus, the correct option is $D$.

The coefficients $x, y, p, q,$ and $r$ in the following balanced equation are respectively:
$xMnO_4^{2-}{_{\text{(aq)}}} + yH_2O_{\text{(l)}} \rightarrow pMnO_2{_{\text{(s)}}} + qMnO_4^{-}{_{\text{(aq)}}} + rOH^{-}{_{\text{(aq)}}}$

Similar Questions

In the reaction of oxalate with permanganate in acidic medium,the number of electrons involved in producing one molecule of $CO_2$ is

In acidic medium,$K_2Cr_2O_7$ shows oxidising action as represented in the half reaction:
$Cr_2O_7^{2-} + XH^+ + Ye^- \rightarrow 2A + ZH_2O$
$X, Y, Z$ and $A$ are respectively:

Reaction of $Br_2$ with $Na_2CO_3$ in aqueous solution gives sodium bromide and sodium bromate with evolution of $CO_2$ gas. The number of sodium bromide molecules involved in the balanced chemical equation is

What will be the value of $x$ and $y$ by balancing the reaction
$C_2H_5OH + xI_2 + yOH^{-} \to CHI_3 + HCO_2^- + 5I^{-} + 5H_2O$

Observe the following reaction: $I_2 + 10 HNO_3 \rightarrow 2 HIO_3 + 10 NO_2 + 4 H_2O$. The equivalent weight of $HNO_3$ is (molar mass of $HNO_3 = M$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The coefficients $x, y, p, q,$ and $r$ in the following balanced equation are respectively: $xMnO_4^{2-}{_{\text{(aq)}}} + yH_2O_{\text{(l)}} \rightarrow pMnO_2{_{\text{(s)}}} + qMnO_4^{-}{_{\text{(aq)}}} + rOH^{-}{_{\text{(aq)}}}$