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(B) In the photoelectric effect experiment,the emitter plate emits electrons when light falls on it. When a vertically downward electric field is appl

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The kinetic energy of the electrons will increase.

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(B) In the photoelectric effect experiment,the emitter plate emits electrons when light falls on it. When a vertically downward electric field is applied,the electrons (which are negatively charged) experience an upward force,$F = qE$,opposite to the direction of the electric field. Since the collector plate is placed vertically above the emitter plate,this upward force acts in the direction of the motion of the electrons towards the collector plate. As a result,the electrons are accelerated,which increases their kinetic energy $(K.E.)$. Because the kinetic energy of the photoelectrons increases,a higher retarding potential is required to stop them,meaning the stopping potential will increase. The saturation photocurrent depends only on the intensity of the incident light and the number of photoelectrons emitted per second,so it remains unchanged.

The collector plate in an experiment on the photoelectric effect is kept vertically above the emitter plate. $A$ light source is turned on,and a saturation photocurrent is recorded. An electric field is then switched on,which has a vertically downward direction.

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