The combustion enthalpies of carbon,hydrogen, | vedclass

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Question

(C) The formation reaction of methane is: $C(s) + 2H_2(g) \rightarrow CH_4(g)$.The standard enthalpy of formation is given by the formula: $\Delta H_f

Vedclass · Accepted Answer

$-72.7$

Vedclass · Answer

(C) The formation reaction of methane is: $C(s) + 2H_2(g) ightarrow CH_4(g)$.The standard enthalpy of formation is given by the formula: $\Delta H_f^\circ(CH_4) = \Delta H_c^\circ(C) + 2 	imes \Delta H_c^\circ(H_2) - \Delta H_c^\circ(CH_4)$.Substituting the given values:$\Delta H_f^\circ(CH_4) = -393.5 + 2(-284.8) - (-890.4)$.$\Delta H_f^\circ(CH_4) = -393.5 - 569.6 + 890.4$.$\Delta H_f^\circ(CH_4) = -72.7 \ kJ/mole$.

The combustion enthalpies of carbon,hydrogen,and methane are $-393.5 \ kJ/mole$,$-284.8 \ kJ/mole$,and $-890.4 \ kJ/mole$ respectively at $25 \ ^oC$. The value of the standard formation enthalpy of methane at that temperature is ..... $kJ/mole$.

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