The complete combustion of one mole of benzen | vedclass

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Question

(C) The molecular formula of benzene is $C_6H_6$. The balanced chemical equation for the complete combustion of benzene is: $C_6H_6(l) + \frac{15}{2}

Vedclass · Accepted Answer

$264$

Vedclass · Answer

(C) The molecular formula of benzene is $C_6H_6$. The balanced chemical equation for the complete combustion of benzene is: $C_6H_6(l) + \frac{15}{2} O_2(g) ightarrow 6 CO_2(g) + 3 H_2O(l)$ From the stoichiometry of the reaction,$1 	ext{ mole}$ of benzene produces $6 	ext{ moles}$ of carbon dioxide $(CO_2)$. The molar mass of $CO_2$ is $12 + (2 	imes 16) = 44 \ g/mol$. Therefore,the mass of $6 	ext{ moles}$ of $CO_2$ is $6 	imes 44 \ g = 264 \ g$. Thus,the complete combustion of one mole of benzene produces $264 \ g$ of carbon dioxide.

The complete combustion of one mole of benzene produces how many grams of carbon dioxide?

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