The complex [Co(NH_3)_5Br]SO_4 will give a wh | vedclass

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(B) The complex $[Co(NH_3)_5Br]SO_4$ ionizes in an aqueous solution to give $[Co(NH_3)_5Br]^{2+}$ and $SO_4^{2-}$ ions.When $BaCl_2$ is added to the s

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$BaCl_2$

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(B) The complex $[Co(NH_3)_5Br]SO_4$ ionizes in an aqueous solution to give $[Co(NH_3)_5Br]^{2+}$ and $SO_4^{2-}$ ions.When $BaCl_2$ is added to the solution,the $SO_4^{2-}$ ions react with $Ba^{2+}$ ions to form a white precipitate of $BaSO_4$.The chemical reaction is: $[Co(NH_3)_5Br]SO_4 + BaCl_2 \rightarrow [Co(NH_3)_5Br]Cl_2 + BaSO_4 \downarrow$ (white precipitate).Therefore,the correct reagent is $BaCl_2$.

The complex $[Co(NH_3)_5Br]SO_4$ will give a white precipitate with:

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