Class 11Chemistry1 Organic Chemistry: Classification and Nomenclature of Organic CompoundsBonding and hybridisation in organic compounds
MediumThe compound in which carbon uses only its $sp^3$ hybrid orbitals for bond formation is
- A$HCOOH$
- B$(NH_2)_2CO$
- C$(CH_3)_3COH$
- D$(CH_3)_3CHO$
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Similar Questions
What is the increasing order of stability of carbanions with the change in hybridization of the carbon atom bearing the negative charge?
Medium
View SolutionThe hybridisations of carbon-$2$ in $P$ and $Q$ are respectively:
The compound having both $sp$ and $sp^{2}$ hybridised carbon atoms is
MediumIIT 1981
View SolutionAmong the following compounds,which have more than one type of hybridization for carbon atoms?
$(i) CH_3CH_2CH_2CH_3$
$(ii) CH_3-CH=CH-CH_3$
$(iii) CH_2=CH-C\equiv CH$
$(iv) HC\equiv CH$
$(i) CH_3CH_2CH_2CH_3$
$(ii) CH_3-CH=CH-CH_3$
$(iii) CH_2=CH-C\equiv CH$
$(iv) HC\equiv CH$
Medium
View SolutionNumber of $sp$ hybridised carbon atoms in the given compound is:
$CH_2 = CH - C \equiv C - CH_2 - CN$
$CH_2 = CH - C \equiv C - CH_2 - CN$
Medium
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