The compound most likely to decolourize a sol | vedclass

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(C) The correct answer is $C$. $CH_3-CH=CH-CH_2-CH_3$ is an alkene (pent$-2-$ene). Alkenes contain a carbon-carbon double bond,which undergoes oxidati

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$CH_3-CH=CH-CH_2-CH_3$

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(C) The correct answer is $C$. $CH_3-CH=CH-CH_2-CH_3$ is an alkene (pent$-2-$ene). Alkenes contain a carbon-carbon double bond,which undergoes oxidation with cold dilute alkaline $KMnO_4$ (Baeyer's reagent) to form vicinal diols,resulting in the decolourization of the purple $KMnO_4$ solution. Option $A$ is an alkane,option $B$ is naphthalene (an aromatic hydrocarbon),and option $D$ is an alkane,none of which react with cold dilute $KMnO_4$ under standard conditions.

The compound most likely to decolourize a solution of potassium permanganate is

Similar Questions

Identify the major product $A$ and major product $B$ in the following set of reactions:
$CH_3-CH=CH_2 \xrightarrow{H_2O, H^+} \text{Major product } A$
$CH_3-CH=CH_2 \xrightarrow{(BH_3)_2, H_2O_2, OH^-} \text{Major product } B$

Alkenes convert into alcohols by:

For which of the following reactions is Markovnikov's rule most applicable?

Which one of the following compounds gives acetone $(CH_3)_2C=O$ as one of the products of its ozonolysis?

Write in detail about the hydrogenation of unsaturated hydrocarbons.

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