The compound which undergoes S_{N^1} reaction | vedclass

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Question

(B) The rate of $S_{N^1}$ reaction is directly proportional to the stability of the carbocation intermediate formed during the rate-determining step.$

Vedclass · Accepted Answer

$3-$Bromocyclohexene

Vedclass · Answer

(B) The rate of $S_{N^1}$ reaction is directly proportional to the stability of the carbocation intermediate formed during the rate-determining step.$(a)$ Cyclohexyl bromide forms a secondary carbocation.$(b)$ $3-$Bromocyclohexene forms an allylic carbocation,which is resonance-stabilized.$(c)$ Cyclohexylmethyl bromide forms a primary carbocation.$(d)$ Bicyclo[$2.2$.$2$]octyl bromide forms a bridgehead carbocation,which is highly unstable due to Bredt's rule.Since the allylic carbocation formed in option $(b)$ is the most stable among the given choices,$3$-Bromocyclohexene undergoes $S_{N^1}$ reaction most rapidly.

The compound which undergoes $S_{N^1}$ reaction most rapidly is

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