The compound with molecular formula C_6H_6,wh | vedclass

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(A) The molecular formula $C_6H_6$ corresponds to a degree of unsaturation of $4$ $(C_n H_{2n+2} - C_n H_m / 2 = (2(6)+2-6)/2 = 4)$.This means the mol

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$8$

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(A) The molecular formula $C_6H_6$ corresponds to a degree of unsaturation of $4$ $(C_n H_{2n+2} - C_n H_m / 2 = (2(6)+2-6)/2 = 4)$.This means the molecule has $4$ double bonds or equivalent unsaturation (rings/triple bonds).The compound takes up $4$ moles of $H_2$ for complete hydrogenation,confirming it has $4$ $\pi$ bonds.Each $\pi$ bond contains $2$ $\pi$ electrons,so $4$ $\pi$ bonds contain $4 	imes 2 = 8$ $\pi$ electrons.The compound is $1,3,5$-trimethylenecyclohexane or a similar isomer that is highly symmetric to yield only one monobromo derivative.Thus,the number of $\pi$ electrons is $8$.

The compound with molecular formula $C_6H_6$,which gives only one monobromo derivative and takes up four moles of hydrogen per mole for complete hydrogenation,has $................\pi$ electrons.

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