The conductivity of $0.005 \ M$ $NaI$ solution at $25^{\circ} C$ is $6.07 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$. Calculate its molar conductivity.

Which of the following $M$ $KCl$ solutions has the lowest value of equivalent conductance?

What is the value of conductivity of $0.01 \ M$ solution of an electrolyte having molar conductivity $141 \ \Omega^{-1} \ cm^2 \ mol^{-1}$?

Write the formula to calculate conductivity by using a conductivity cell.

Molar conductivity of $0.04 \ M \ BaCl_2$ solution is $230 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ at $27^{\circ} C$. What is its conductivity?

The resistance of a conductivity cell containing $0.01 \, M \, KCl$ solution at $298 \, K$ is $1750 \, \Omega$. If the conductivity of $0.01 \, M \, KCl$ solution at $298 \, K$ is $0.152 \times 10^{-3} \, S \, cm^{-1}$,then the cell constant of the conductivity cell is $.......... \, \times 10^{-3} \, cm^{-1}$.