The conductivity of $0.3 \ M$ solution of $KCl$ at $298 \ K$ is $0.0627 \ S \ cm^{-1}$. What is its molar conductivity?

The specific conductance of $0.05 \ M$ $NaOH$ solution is $0.0115 \ S \ cm^{-1}$. What is its molar conductance $(\Lambda_{m})$ in $S \ cm^2 \ mol^{-1}$?

Given below are two statements $:$
Statement $I :$ Mohr's salt is composed of only three types of ions$-$ferrous,ammonium and sulphate.
Statement $II :$ If the molar conductance at infinite dilution of ferrous,ammonium and sulphate ions are $x_1, x_2$ and $x_3 \ S \ cm^2 \ mol^{-1}$,respectively then the molar conductance for Mohr's salt solution at infinite dilution would be given by $x_1+x_2+2 x_3$
In the light of the given statements,choose the correct answer from the options given below $:$

At $25\,^{\circ}C$,the specific conductivity of a normal solution of $KCl$ is $0.002765\,S\,cm^{-1}$. The resistance of the cell is $400\,\Omega$. The cell constant is: (in $,cm^{-1}$)

The electrical conductance of unit volume $(1 \ cm^3)$ of solution is called as

Equivalent conductances of $BaCl_2$,$H_2SO_4$ and $HCl$ at infinite dilution are $\Lambda_1^\infty$,$\Lambda_2^\infty$ and $\Lambda_3^\infty$ respectively. Then,the equivalent conductance of $BaSO_4$ at infinite dilution will be: