The constraints -x_{1} + x_{2} leq 1,-x_{1} + | vedclass

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(B) To determine the nature of the feasible region,we analyze the given constraints:$1$) $-x_{1} + x_{2} \leq 1$$2$) $-x_{1} + 3x_{2} \leq 9$$3$) $x_{

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unbounded feasible space

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(B) To determine the nature of the feasible region,we analyze the given constraints:$1$) $-x_{1} + x_{2} \leq 1$$2$) $-x_{1} + 3x_{2} \leq 9$$3$) $x_{1}, x_{2} \geq 0$Plotting these lines on the Cartesian plane:- For $-x_{1} + x_{2} = 1$,the intercepts are $(0, 1)$ and $(-1, 0)$.- For $-x_{1} + 3x_{2} = 9$,the intercepts are $(0, 3)$ and $(-9, 0)$.The non-negativity constraints $x_{1}, x_{2} \geq 0$ restrict the region to the first quadrant.By observing the intersection of the half-planes defined by the inequalities,we find that the region extends infinitely in the direction of increasing $x_{1}$.Therefore,the feasible region is an unbounded feasible space.

The constraints $-x_{1} + x_{2} \leq 1$,$-x_{1} + 3x_{2} \leq 9$,$x_{1}, x_{2} \geq 0$ define:

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