The conversion of 2,3-dibromobutane to 2-bute | vedclass

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(C) The reaction of $2,3-$dibromobutane with $Zn$ dust is a dehalogenation reaction. In this process,two bromine atoms are removed from adjacent carbo

Vedclass · Accepted Answer

$\beta-$Elimination

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(C) The reaction of $2,3-$dibromobutane with $Zn$ dust is a dehalogenation reaction. In this process,two bromine atoms are removed from adjacent carbon atoms ($C2$ and $C3$),resulting in the formation of a double bond between them to produce $2-$butene. This type of elimination,where atoms are removed from adjacent carbons,is known as $\beta-$elimination.

The conversion of $2,3-$dibromobutane to $2-$butene with $Zn$ is

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