The coordinates of the midpoint of a line seg | vedclass

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Question

(A) The midpoint formula for a line segment joining points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2

Vedclass · Accepted Answer

$(1, 1)$

Vedclass · Answer

(A) The midpoint formula for a line segment joining points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$ Given points are $A(3, -2)$ and $B(-1, 4)$. Here,$x_1 = 3, y_1 = -2$ and $x_2 = -1, y_2 = 4$. Substituting these values into the formula: $M = \left( \frac{3 + (-1)}{2}, \frac{-2 + 4}{2} \right)$ $M = \left( \frac{2}{2}, \frac{2}{2} \right)$ $M = (1, 1)$ Therefore,the coordinates of the midpoint are $(1, 1)$.

The coordinates of the midpoint of a line segment joining $A (3, -2)$ and $B (-1, 4)$ are:

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