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(B) To find the maximum value of the objective function $z=4x+3y$,we evaluate $z$ at each corner point of the feasible region:						Corner point $(x,

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The quantity in column $B$ is greater

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(B) To find the maximum value of the objective function $z=4x+3y$,we evaluate $z$ at each corner point of the feasible region:						Corner point $(x, y)$			Value of $z=4x+3y$							$(0,0)$			$z=4(0)+3(0)=0$							$(0,40)$			$z=4(0)+3(40)=120$							$(20,40)$			$z=4(20)+3(40)=200$							$(60,20)$			$z=4(60)+3(20)=300$							$(60,0)$			$z=4(60)+3(0)=240$			The maximum value of the objective function $z$ is $300$.Comparing this with Column $B$ $(325)$,we see that $300 Therefore,the quantity in Column $B$ is greater.

The corner points of the feasible region determined by the system of linear constraints are $(0,0), (0,40), (20,40), (60,20), (60,0)$. The objective function is $z=4x+3y$. Compare the quantity in Column $A$ and Column $B$.

Column Value

$A$. Maximum of $z$ $300$

$B$. Constant value $325$

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The corner points of the feasible region determined by the system of linear constraints are $(0,0), (0,40), (20,40), (60,20), (60,0)$. The objective function is $z=4x+3y$. Compare the quantity in Column $A$ and Column $B$. Column Value $A$. Maximum of $z$ $300$ $B$. Constant value $325$