The correct bond order of the B-F bond in the | vedclass

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(D) In the $BF_3$ molecule, the boron atom is electron-deficient and completes its octet through back-bonding from the fluorine atoms. This results in

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$1 \frac{1}{3}$

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(D) In the $BF_3$ molecule, the boron atom is electron-deficient and completes its octet through back-bonding from the fluorine atoms. This results in resonance structures where one $B-F$ bond has a double bond character while the other two remain single bonds.There are $3$ contributing resonance structures.In each structure, one bond is a double bond (order $2$) and two are single bonds (order $1$).The average bond order is calculated as:$	ext{Bond Order} = \frac{	ext{Total number of bonds}}{	ext{Number of resonating positions}} = \frac{2 + 1 + 1}{3} = \frac{4}{3} = 1 \frac{1}{3}$.

The correct bond order of the $B-F$ bond in the $BF_3$ molecule is:

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