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(B) The complex $K_3[Fe(CN)_6]$ dissociates as $3K^+ + [Fe(CN)_6]^{3-}$.Let the oxidation state of $Fe$ be $x$.In the complex ion $[Fe(CN)_6]^{3-}$,th

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$+3, 6$

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(B) The complex $K_3[Fe(CN)_6]$ dissociates as $3K^+ + [Fe(CN)_6]^{3-}$.Let the oxidation state of $Fe$ be $x$.In the complex ion $[Fe(CN)_6]^{3-}$,the charge on $CN^-$ is $-1$.So,$x + 6(-1) = -3$.$x - 6 = -3 \Rightarrow x = +3$.The coordination number is the number of ligand donor atoms bonded to the central metal ion. Since $6$ $CN^-$ ligands are attached,the coordination number is $6$.

The correct charge and coordination number of $Fe$ in $K_3[Fe(CN)_6]$ is

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