The correct electronic configuration and spin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The atomic number of Gadolinium $(Gd)$ is $Z = 64$.Its ground state electronic configuration is $[Xe] 4f^7 5d^1 6s^2$.For the $Gd^{3+}$ ion,three

Vedclass · Accepted Answer

$[Xe] 4f^7$ and $7.9$

Vedclass · Answer

(B) The atomic number of Gadolinium $(Gd)$ is $Z = 64$.Its ground state electronic configuration is $[Xe] 4f^7 5d^1 6s^2$.For the $Gd^{3+}$ ion,three electrons are removed (one from $5d$ and two from $6s$):$Gd^{3+} = [Xe] 4f^7$.Here,there are $7$ unpaired electrons $(n = 7)$ in the $4f$ orbital.The formula for the spin-only magnetic moment $(\mu)$ is $\mu = \sqrt{n(n+2)} \ B.M.$$\mu = \sqrt{7(7+2)} = \sqrt{7 	imes 9} = \sqrt{63} \approx 7.9 \ B.M.$Therefore,the correct option is $B$.

The correct electronic configuration and spin-only magnetic moment $(B.M.)$ of $Gd^{3+}$ $(Z = 64)$ are respectively:

Similar Questions

Identify the metal that forms colourless compounds.

Which ion has the maximum magnetic moment?

Which of the following transition metals can exhibit the highest oxidation state?

The tendency towards complex formation is maximum in

Vedclass Test Series

Exam Paper Generator

Online Exam Module