The correct electronic configuration of Ti (Z | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic number of Titanium $(Ti)$ is $Z = 22$. According to the Aufbau principle,electrons are filled in orbitals in increasing order of energy

Vedclass · Accepted Answer

$1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2$

Vedclass · Answer

(A) The atomic number of Titanium $(Ti)$ is $Z = 22$. According to the Aufbau principle,electrons are filled in orbitals in increasing order of energy: $1s, 2s, 2p, 3s, 3p, 4s, 3d$. Filling $22$ electrons: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6$ accounts for $18$ electrons. The remaining $4$ electrons are filled as $4s^2$ and $3d^2$. Thus,the configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2$.

The correct electronic configuration of $Ti$ $(Z = 22)$ atom is:

Similar Questions

What are core electrons and valence electrons?

How many orbitals is/are possible with $n=3$,$l=1$ and $m_l=-1$ values?

Which of the following arrangements shows the correct order of decreasing paramagnetism?

$Ge$ $(Z=32)$ in its ground state electronic configuration has $x$ completely filled orbitals with $m_{l}=0$. The value of $x$ is ..... .

The orbital angular momentum of an electron in an orbital is given by $\sqrt{l(l + 1)} \cdot \frac{h}{2\pi}$. For an $s$-electron,this momentum is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module