The correct match for the complex with its ma | vedclass

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Question

(B) $1$. For $[Zn(OH_2)_6]^{2+}$: $Zn^{2+}$ is $3d^{10}$,which has no unpaired electrons,so it is diamagnetic.$2$. For $[Co(NH_3)_6]^{3+}$: $Co^{3+}$

Vedclass · Accepted Answer

$[Co(NH_3)_6]^{3+}$; diamagnetic

Vedclass · Answer

(B) $1$. For $[Zn(OH_2)_6]^{2+}$: $Zn^{2+}$ is $3d^{10}$,which has no unpaired electrons,so it is diamagnetic.$2$. For $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons. It forms $d^2sp^3$ hybridization with no unpaired electrons,making it diamagnetic.$3$. For $[CoF_6]^{3-}$: $Co^{3+}$ is $3d^6$. $F^-$ is a weak field ligand,so no pairing occurs. It has $4$ unpaired electrons,making it paramagnetic.$4$. For $[V(OH_2)_6]^{2+}$: $V^{2+}$ is $3d^3$,which has $3$ unpaired electrons,making it paramagnetic.Therefore,the correct match is $[Co(NH_3)_6]^{3+}$; diamagnetic.

List $I$ (Complex)	List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$	$I$. Optical
$B$. $[Co(en)_3]^{3+}$	$II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$	$III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$	$IV$. Linkage

The correct match for the complex with its magnetic behavior is:

Similar Questions

The magnetic moment of $Ni^{2+}$ in an aqueous solution is ......... $B.M.$

The correct order of the spin-only magnetic moments of the following complexes is
$(I) [Cr(H_2O)_6]Br_2$
$(II) Na_4[Fe(CN)_6]$
$(III) Na_3[Fe(C_2O_4)_3] (\Delta_0 > P)$
$(IV) (Et_4N)_2[CoCl_4]$

Match List $I$ with List $II$ :
List $I$ (Complex) List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$ $I$. Optical
$B$. $[Co(en)_3]^{3+}$ $II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$ $III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$ $IV$. Linkage

Choose the correct answer from the options given below :

Square planar complex of the type $MAXBL$ (where $A, B, X$ and $L$ are unidentate ligands) shows which of the following sets of isomers?

The species with spin only magnetic moment of $\sqrt{24} \, BM$ is

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