The correct options for the products A and B | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. When phenol reacts with bromine water ($Br_2$ in $H_2O$),the highly activating $-OH$ group causes rapid electrophilic substitution at all ort

Vedclass · Accepted Answer

Vedclass · Answer

(A) $1$. When phenol reacts with bromine water ($Br_2$ in $H_2O$),the highly activating $-OH$ group causes rapid electrophilic substitution at all ortho and para positions,resulting in the formation of $2,4,6$-tribromophenol as product $A$.$2$. When phenol reacts with bromine in a non-polar solvent like carbon disulfide $(CS_2)$ at low temperature $(< 5^{\circ}C)$,the reaction is less vigorous,leading to monobromination. The major product $B$ is $p$-bromophenol due to steric hindrance at the ortho position.

The correct options for the products $A$ and $B$ of the following reactions are:

Similar Questions

The oxidation of phenol with chromic acid gives

The phthalein test is a characteristic test for which of the following?

Ortho and para nitrophenols are more acidic than phenol. Draw the resonance structures of the corresponding phenoxide ions.

Arrange the following compounds in decreasing order of their acidic strength:

Phenol is treated with bromine water and shaken well. The white precipitate formed during the process is

Vedclass Test Series

Exam Paper Generator

Online Exam Module