The correct order of 2^{nd} ionisation potent | vedclass

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(C) The $2^{nd}$ ionisation potential corresponds to the energy required to remove an electron from a unipositive ion $(M^+)$.The electronic configura

Vedclass · Accepted Answer

$O > F > N > C$

Vedclass · Answer

(C) The $2^{nd}$ ionisation potential corresponds to the energy required to remove an electron from a unipositive ion $(M^+)$.The electronic configurations of the unipositive ions are:$C^+ (1s^2 2s^2 2p^1)$$N^+ (1s^2 2s^2 2p^2)$$O^+ (1s^2 2s^2 2p^3)$$F^+ (1s^2 2s^2 2p^4)$$O^+$ has a stable half-filled $2p^3$ configuration,which makes it very difficult to remove the second electron,resulting in the highest $2^{nd}$ ionisation potential.Comparing the others,$F^+$ has a higher effective nuclear charge than $N^+$,and $N^+$ has a higher effective nuclear charge than $C^+$.Thus,the correct order is $O > F > N > C$.

The correct order of $2^{nd}$ ionisation potential of carbon,nitrogen,oxygen and fluorine is

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