The correct order of pK_{a} of the following | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The acidity of carboxylic acids is directly proportional to the stability of their conjugate bases,which is enhanced by electron-withdrawing group

Vedclass · Accepted Answer

$(II) < (I) < (III) < (IV)$

Vedclass · Answer

(D) The acidity of carboxylic acids is directly proportional to the stability of their conjugate bases,which is enhanced by electron-withdrawing groups ($-I$ effect).$pK_a$ is inversely proportional to acidity.Comparing the compounds:$II. CF_3COOH$ (Strongest acid due to three highly electronegative $F$ atoms)$I. CCl_3COOH$ (Strong acid,but $Cl$ is less electronegative than $F$)$III. NO_2CH_2COOH$ (Stronger acid than $IV$ because $-NO_2$ is a stronger electron-withdrawing group than $-CN$)$IV. NCCH_2COOH$Acidity order: $II > I > III > IV$Since $pK_a = -\log(K_a)$,the order of $pK_a$ is the reverse of the acidity order:$pK_a$ order: $IV > III > I > II$This corresponds to $(II) < (I) < (III) < (IV)$.

The correct order of $pK_{a}$ of the following compounds is:
$I. CCl_3COOH$
$II. CF_3COOH$
$III. NO_2CH_2COOH$
$IV. NCCH_2COOH$

Similar Questions

Which of the following compounds is most reactive towards Grignard's reagent?

Which of the following is most acidic?

What is the reason for the solubility of low molecular weight carboxylic acids in water?

Identify the reagent $R$ necessary to bring about the following conversion: $C_6H_5COCl \xrightarrow{R} C_6H_5COOH$.

Sodium acetate reacts with acetyl chloride to form

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct order of $pK_{a}$ of the following compounds is:$I. CCl_3COOH$$II. CF_3COOH$$III. NO_2CH_2COOH$$IV. NCCH_2COOH$